From a height of 2.45 m, a ball falls from rest to the floor. Determine its speed at the moment

From a height of 2.45 m, a ball falls from rest to the floor. Determine its speed at the moment it touches the floor. Disregard air friction.

These tasks: state of rest (V0 (initial ball velocity) = 0 m / s); h0 (original height) = 2.45 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

Option 1) The law of conservation of energy: Ek0 + Ep0 = Ek + Ep; 0 + Ep0 = Ek + 0; m * g * h0 = m * V ^ 2/2 and V = √ (g * h0 * 2) = √ (10 * 2.45 * 2) = 7 m / s.

Option 2) The law of motion of the body: S = h0 = V ^ 2 / 2a = V ^ 2 / 2g, whence V = √ (2g * h0) = 7 m / s.

Answer: At the moment of touching the floor, the ball will reach a speed of 7 m / s.