From a height of 20 m, a body is thrown vertically upward, giving it a speed of 10 m / s.

From a height of 20 m, a body is thrown vertically upward, giving it a speed of 10 m / s. At what height the potential energy of the body will be equal to the kinetic one.

Data: h0 (original body height) = 20 m; V0 (velocity imparted to the body) = 10 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

When the body reaches the desired height, the equality (energy conservation law) will be fulfilled: Ek0 + Eп0 = 2Eп; m * V0 ^ 2/2 + m * g * h0 = 2 * m * g * h, whence h = (V0 ^ 2/2 + g * h0) / (2 * g).

Let’s calculate: h = (10 ^ 2/2 + 10 * 20) / (2 * 10) = 12.5 m.

Answer: The body will be at a height of 12.5 m (it will reach its maximum height and begin to fall).