From a height of 446 m, the parachutist descended uniformly for 2 minutes 5 seconds. What is the speed of the skydiver?

Initial data: H (initial height from which the parachutist descended uniformly) = 446 m; t (duration of descent) = 2 min 5 s.

SI system: t = 2 min 5 s = 2 * 60 + 5 = 125 s.

The skydiver’s speed can be calculated using the formula: V = S / t.

Let’s calculate: V = 446/125 = 3.568 m / s or 12.8448 km / h.

Answer: The speed of the parachutist is 3.568 m / s.



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