From a mine 60 m deep, 1 ton of ore is lifted with a hoist in 20 seconds. Determine the power of the lift motor.

univerkov | August 10, 2021 | education

Initial data: h (mine depth) = 60 m; mр (mass of ore raised from the mine) = 1 t (1 * 10 ^ 3 kg); t (duration of ore rise) = 20 s.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

The power of the hoist motor is calculated by the formula: N = A / t = ΔEp / t = mr * g * h / t.

Calculation: N = 1 * 10 ^ 3 * 10 * 60/20 = 30 * 10 ^ 3 W (30 kW).

Answer: The power of the hoist motor is 30 kW.

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