From a point located at a distance of 6 cm from the plane, two inclined ones are drawn. Find the distance between

From a point located at a distance of 6 cm from the plane, two inclined ones are drawn. Find the distance between the bases of the inclined, if the angle between the inclined and its projection is 30 degrees, and between the projections – 120 degrees.

In a right-angled triangle AOB, we define the length of the leg OA through the known leg and angle. tg30 = BO / AO.

AO = BО / tg30 = 6 / (1 / √3) = 6 * √3 cm.

Similarly, in a triangle BОС СО = 6 * √3 cm.

In the triangle AOB, by the cosine theorem, we determine the length of the segment AC.

AC ^ 2 = AO ^ 2 + CO ^ 2 – 2 * AO * CO * Cos120 = 108 + 108 – 2 * 6 * √3 * 6 * √3 * (-1 / 2) = 216 + 108 = 324.

AC = 18 cm.

Answer: The speaker distance is 18 cm.



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