# From a rectangle, the length of which is 12 dm, and this is 3 times more than the width

**From a rectangle, the length of which is 12 dm, and this is 3 times more than the width, a square with a side of 6 dm was cut out. Find the area of the remaining part.**

1.To solve the problem, you need to find the difference between the area of the rectangle and the square cut out of it.

2. Find the width of the rectangle if it is known that it is 3 times less than the length:

12/3 = 4 dm.

3. Find the area of a rectangle by the formula S = a * b, where S is the area of a rectangle with sides a and b:

S rectangle = 12 * 4 = 48 dm2.

4. Find the area of the cut out square by the formula S = a * a, where S is the area of a square with side a:

6 * 6 = 36 dm2.

5. Find the difference between the areas of a square and a rectangle:

48 – 36 = 12 dm2.

Answer: the area of the remaining part of the rectangle is 12 dm2.