From a stationary boat, the mass of which, together with a person and a load = 190 kg, is thrown onto the shore

From a stationary boat, the mass of which, together with a person and a load = 190 kg, is thrown onto the shore a bag of sand = 7 kg, with a horizontal speed relative to the Earth = 6 m / s. What speed will the boat gain after the throw?

To find the speed acquired by the boat after throwing the bag, we apply the law of conservation of momentum: mm * Vm = (m – mm) * V, whence we express: V = mm * Vm / (m – mm).

The values of the variables: mm is the mass of the sand bag (mm = 7 kg); Vm – speed of throwing the bag (Vm = 6 m / s); m is the total mass of the boat, person and bag (m = 190 kg).

Let’s calculate: V = mm * Vm / (m – mm) = 7 * 6 / (190 – 7) = 42/183 = 0.23 m / s.

Answer: The boat, after throwing a sandbag, will acquire a speed of 0.23 m / s.



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