From a stationary helicopter, located at an altitude of 880 m, a shot is fired vertically downward.

From a stationary helicopter, located at an altitude of 880 m, a shot is fired vertically downward. How long does it take for a bullet to reach the ground if its velocity is 200 m / s?

Data: the helicopter is stationary; h (height of the helicopter above the ground, distance covered by the bullet) = 880 m; the bullet moves vertically down; V0 (muzzle velocity) = 200 m / s.
Reference values: g (acceleration of gravity, acceleration of a bullet) ≈ 10 m / s2.
The time when the bullet reaches the ground is determined by the formula: S = h = V0 * t + 0.5 * g * t ^ 2.
0.5 * 10 * t ^ 2 + 200 * t – 880 = 0.
t ^ 2 + 40t – 176 = 0.
By Vieta’s theorem: t1 = 4 s (true); t2 = -44 c (not true).
Answer: The bullet will reach the ground in 4 seconds.