From a well 200 m deep, 150 m3 of water must be pumped out. Pump power 14.7 kW.

From a well 200 m deep, 150 m3 of water must be pumped out. Pump power 14.7 kW. How long does it take for the pump to do this job?

Given: h (well depth) = 200 m; V (volume of water to be pumped out) = 150 m3; N (power of the pump used) = 14.7 kW (14.7 * 10^3 W).

Constants: g (acceleration due to gravity) = 9.81 m / s2; ρw (density of pumped water) = 1000 kg / m3.

The time required for the pump to pump out 150 m3 of water is determined by the formula: t = A / N = m * g * h / N = ρw * V * g * h / N.

Calculation: t = 1000 * 150 * 9.81 * 200 / (14.7 * 10 ^ 3) = 20020 s = 5 h 33 min 40 s.

Answer: The pump will cope in 5 hours 33 minutes 40 seconds.