From an urn containing 7 red and 9 blue balls, take out two balls one after the other. Find the probability

From an urn containing 7 red and 9 blue balls, take out two balls one after the other. Find the probability of removing the blue ball twice.

There are 7 + 9 = 16 balls in the urn.
The probability that the first ball drawn is blue:
p1 = 9/16;
The conditional probability that the second ball taken out is blue, provided that the first one was blue:
p2 = 8/15;
Probability of drawing a blue ball twice:
P = p1 * p2 = 9/16 * 8/15 = 0.3;
Answer: 0.3.