From cities A and B, located at a distance of 275 km from each other, two trains left simultaneously in opposite
From cities A and B, located at a distance of 275 km from each other, two trains left simultaneously in opposite directions. One of them was walking at a speed of 75 km / h. At what distance from each other will these trains be 6 hours after the start of movement?
Let’s write down the speed of the second train as x km / h.
In this case, the speed of the trains moving away will be:
75 + x km / h.
In 6 hours the trains will pass:
6 * (75 + x) = 450 + 6 * x.
Find the distance between trains in 6 hours.
To do this, add the distance that the trains will travel to the initial distance.
We get:
275 + 450 + 6 * x = 725 + 6 * x km.
If we represent the speed of the second train as an integer, we get:
x = 50 km.
275 + 450 + 6 * 50 = 725 + 300 = 1025 km.
Answer: In 6 hours there will be 725 + 6 * km between trains.