From cities A and B, the distance between which was 164.7 km was driven towards each other by a truck

From cities A and B, the distance between which was 164.7 km was driven towards each other by a truck from city A and a passenger car from city B. The speed of a truck is 36 km / h, and a passenger car is 1.25 times higher. The passenger car left 1.2 hours later than the truck. How long will it take and at what distance from city B will a passenger car meet a truck?

Since the speed of a passenger car is 1.25 times higher, it will be:

36 * 1.25 = 45 km / h.

Let’s take x time before the meeting of a passenger car, then:

x + 1.2 – freight time;

45 * x – distance covered by a passenger car;

36 * (x + 1.2) – distance traveled by the cargo.

We get the equation:

45x + 36 * (x + 1.2) = 164.7;

81x = 164.7 – 43.2 = 121.5;

x = 1.5.

During this time, the passenger car passed:

45 * 1.5 = 67.5 km.

Answer: the meeting took place 1.5 hours after the departure of the car at a distance of 67.5 km.