From city A to city B, the distance between which is 300 km, a bus departed. 20 minutes later a car left B to A towards

From city A to city B, the distance between which is 300 km, a bus departed. 20 minutes later a car left B to A towards him and 2 hours after the departure met a bus. At what speed the car was traveling if it was known that it was at 20 km / h more bus speed?

Let the car was traveling at a speed of (x) km / h, then the bus – at a speed of (x – 20) km / h. Travel time for the bus is 2 hours, and for the car for 20 minutes. = 1/3 h less, i.e. 1 2/3 hours. Before the meeting, the bus passed (x – 20) * 2 km, and the car – (1 2/3 * x) km. The whole path is (2 (x – 20) + 1 1 / 3x) km or 300 km. Let’s make an equation and solve it.
2 (x – 20) + 1 1/3 x = 300;
2x – 40 + 1 1/3 x = 300;
3 1/3 x = 300 + 40;
3 1/3 x = 340;
x = 340: 3 1/3;
x = 340: 10/3;
x = 340 * 3/10;
x = 340: 0.3;
x = 102 (km / h)
Answer. 102 km / h.