From city A to city B, the distance between which is 550 km, a motorcyclist left. 4 hours after that, a cyclist left town B

From city A to city B, the distance between which is 550 km, a motorcyclist left. 4 hours after that, a cyclist left town B to meet him and met a motorcyclist 3 hours after his departure. Find the speed of each of them if the motorcyclist travels 90 km more in 3 hours than the cyclist in 6 hours.

x – motorcycle speed
y – bike speed
x (4 + 3) + 3y = 550
3x-6y = 90

7x + 3y = 550 | * 2
3x-6y = 90

14x + 6y = 1100
3x-6y = 90
14x + 6y + 3x-6y = 1100 + 90
17x = 1190

17x = 1190
3x-6y = 90

x = 70
3 * 70-6y = 90

x = 70
210-6y = 90

x = 70
-6y = 90-210

x = 70
-6y = -120

x = 70
y = 20
Answer: motorcycle speed 70 km / h, bike speed 20 km / h