From ethane with a volume of 44.8 liters, you can get carbon dioxide with a volume of …?

Solution:
1. Let’s compose the equation of reactions:
2С2Н6 + 7О2 = 4СО2 + 5Н2О – reaction of ethane combustion, carbon dioxide is released;
2. Determine the number of moles of ethane:
1 mol (C2H6) – 22.4 L;
X mol -44.8 liters. hence, X mol (C2H6) = 1 * 44.8 / 22.4 = 4 mol;
3. Let’s make a proportion according to the reaction equation data:
4 mol (C2H6) – X mol (CO2);
-2 mol – 4 mol from here, X mol (CO2) = 4 * 4/2 = 8 mol;
4. Determine the volume of carbon dioxide according to Avogadro’s law:
V (CO2) = 8 * 22.4 = 179.2 liters.
Answer: during the reaction, carbon dioxide is released in a volume of 179.2 liters.