From magnetic iron ore, consisting mainly of FE3O4, you can get iron by treating iron ore with hydrogen

| August 1, 2021 | education

From magnetic iron ore, consisting mainly of FE3O4, you can get iron by treating iron ore with hydrogen H2 for this process, the corresponding reaction FE3O4 + H2 = Fe + H2o Set the coefficients yourself. Calculate the volume of hydrogen required to obtain a) 42 g of iron b) to process 58 g of Fe3O4

In accordance with the condition of the problem, we write:

Fe3O4 + 4H2 = 3Fe + 4H2O – OBP, iron obtained;
We make calculations:
M (Fe3O4) = 231.4 g / mol;

M (Fe) = 55.8 g / mol;

Y (Fe3O4) = m / M = 58 / 231.4 = 0.25 mol;

Y (Fe) = m / M = 42 / 55.8 = 0.75 mol.

Proportion:
0.25 mol (Fe3O4) – X mol (H2);

-1 mol -4 mol from here, X mol (H2) = 0.25 * 4/1 = 1 mol.

We find the volume of H2:
V (H2) = 1 * 22.4 = 22.4 liters.

Proportion:
X mol (H2) – 0.75 mol (Fe);

-4 mol 3 mol hence, X mol (H2) = 4 * 0.75 / 3 = 1 mol;

V (H2) = 1 * 22.4 = 22.4 liters.

Answer: the volume of hydrogen is 22.4 liters.



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