From one city to another left two motorcyclists, the distance between which is 93 km The speed of the second

From one city to another left two motorcyclists, the distance between which is 93 km The speed of the second motorcyclist is 3 km / h more than the speed of the first. Motorcyclists met at a distance of 45 km from the first city. Find the speed of each motorcyclist.

1) 93 – 45 = 48 (km) the second motorcyclist passed.

2) 48 – 45 = 3 (km) the second rider traveled more than the first.

Timing:

t = S: v, where t is time, S is distance, v is speed.

S – distance difference 3 km.

v – speed difference 3 km / h.

3) 3: 3 = 1 (h) each of the motorcyclists was on the road.

The speed is calculated using the formula:

v = S: t, where v is speed, t is time, S is distance.

4) 45: 1 = 45 (km / h) speed of the first rider.

5) 48: 1 = 48 (km / h) speed of the second rider.



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