From one point of the ring road, the length of which is 12 km, two cars simultaneously drove in one direction.

From one point of the ring road, the length of which is 12 km, two cars simultaneously drove in one direction. The speed of the first car is 101 km / h, and 20 minutes after the start, it was one lap ahead of the second car. Find the speed of the second car. Give your answer in km / h.

So the second car was ahead of the first one by one lap (12 km) in 20 minutes (1/3 hour), then its speed relative to the first is greater by:
12: 1/3 = 36 km / h.
Since the speed of the first is 101 km / h, the speed of the second will be:
101 + 36 = 137 km / h.



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