From point A to bunk B, the distance between which the cyclist was 40 km away at a speed of 40 km / h

| March 23, 2021 | education

From point A to bunk B, the distance between which the cyclist was 40 km away at a speed of 40 km / h when he traveled exactly half the way from A to B, followed by a motorcyclist who caught up with the cyclist 10 km before bunk B, find the speed of convergence between the cyclist and a motorcyclist.

Let us determine how far the cyclist traveled until the moment the motorcyclist left.

40/2 = 20 km.

From the moment the motorcyclist left, the cyclist traveled 10 km.

Let’s define the time for which the cyclist traveled 10 km: 10/40 = 1/4 hour = 0.25 hours.

Then the motorcyclist traveled 10 + 20 = 30 km in 0.25 hours.

Determine the speed of the motorcyclist.

30 / 0.25 = 120 km / h.

Let us determine the speed of convergence between a motorcyclist and a cyclist.

120 – 40 = 80 km / h.

Answer: The approach speed is 80 km / h.



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