From point A to point B, a cyclist left at a speed of 10 km / h. After the cyclist traveled 4 km, a pedestrian

| January 3, 2021 | education

From point A to point B, a cyclist left at a speed of 10 km / h. After the cyclist traveled 4 km, a pedestrian left point A at a speed of 5 km / h, who came to point B 1 hour later than the cyclist. Find the distance between points.

Since the cyclist had traveled 4 km at a speed of 10 km / h by the time the pedestrian exited, he was already on the way:
4:10 = 0.4 hours.
So the pedestrian left 0.4 hours later, but according to the condition of the problem, the pedestrian arrived at the destination an hour later, that is, on the way he was more than a cyclist by:
1 – 0.4 = 0.6 hours.
Suppose the distance from A to B is x. Let’s compose and solve the equation:
x / 10 = x / 5 – 0.6,
x / 10 = (x – 3) / 5,
5 * x = 10 * x – 30,
5 * x = 30,
x = 6 (km).
Answer: 6 km.



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