From point A to point B, the distance between which is 6 km is simultaneously a pedestrian and a cyclist

| April 25, 2021 | education

From point A to point B, the distance between which is 6 km is simultaneously a pedestrian and a cyclist. The cyclist arrives at point B, immediately turns back and meets a pedestrian 36 minutes after leaving A. It is known that the cyclist’s speed is 10 km / h higher than the pedestrian’s speed. How long after they leave A will the distance between them be equal to 2 km?

1. Take the traveler’s speed as x (km / h). Cyclist speed (x + 10) km / h.

2.36 minutes = 0.6 hours.

3. Let’s compose the equation:

0.6x + 0.6 (x + 10) = 6 x 2 = 12;

1.2x + 6 = 12;

x = 5 km / h.

Cyclist speed 5 + 10 = 15 km / h.

4. Taking as x (hours) the time after the start of the movement, after which, between

a traveler and a cyclist will be 2 km.

5. We make the equation:

15x = 5x + 2;

10x = 2;

x = 0.2

Answer: there will be 2 km between the traveler and the cyclist in 0.2 hours after the start of the movement.



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