From point A to point B, which are 330 km distant, two cars leave at the same time towards each other

| May 26, 2021 | education

From point A to point B, which are 330 km distant, two cars leave at the same time towards each other, so that the speed of the car from B of one is twice the speed of the car from A, and they meet in 2 hours. Find the speed of each car and the distance from point A to the meeting point.

S = 330 km.
Vv = 2 * Va.
t = 2 h.
Vа -?
Vв -?
Sa -?
The path Sa, which the car drove from point A before the meeting, will be determined by the formula: Sa = Va * t.
The path Sv, which the car drove from point B before the meeting will be determined by the formula: Sv = Vw * t.
S = Sa + Sv.
S = Va * t + Vb * t = Va * t + 2 * Va * t = 3 * Va * t.
Vа = S / 3 * t.
Vа = 330 km / 3 * 2 h = 55 km / h.
Vv = 2 * 55 km / h = 110 km / h.
Sa = 55 km / h * 2 h = 110 km.
Answer: the speed of the car from point A is Va = 55 km / h, the speed of the car from point B is Vb = 110 km / h, the distance from point A to the place of their meeting is Sa = 110 km.



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