From point B, taken on the circle, the chord BA and the diameter of the BC are drawn, the chord BA

From point B, taken on the circle, the chord BA and the diameter of the BC are drawn, the chord BA contracts the angle of 46 degrees. Find the angle between the chord and the diameter.

In the triangle ABC, the internal angle of the BCA rests on the arc AB, therefore, it is equal to half the value of the arc BA.

BCA angle = 46/2 = 23.

The angle BAC is based on the diameter of the circle, and therefore is equal to 90. Then the triangle ABC is rectangular.

The sum of the angles of the triangle is 180, then the angle between the chord AB and the diameter will be equal to:

Angle ABC = 180 – 90 – 23 = 67.

Answer: The angle between the diameter and the chord is 67.



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