From point M to point N, the distance between which is 80 km, 2 cars left at the same time. On the way, one of the cars stopped for 15 minutes, but arrived at point N 5 minutes earlier than the second. It is known that its speed is 1.5 times the speed of the second one. Find the speed of each car.
Let’s determine how many minutes the first car was in motion less than the second:
15 + 5 = 20.
Let us denote by variable x the speed of movement of the second car.
Therefore, according to the condition of the problem, the speed of the first car can be represented as 1.5x.
Knowing that the first one spent 20 minutes less to overcome the distance equal to 80 kilometers, we will draw up an equation and determine the speed of the cars:
80 / x – 80 / 1.5x = 20/60;
1.5x / 3 = 40;
x = 80;
1.5 * 80 = 120.
Answer: The speed of the first car is 120 km / h, the second – 80.
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