From points A and B, 2 trains departed simultaneously in the same direction. The speed of the first train was 80 km / h

From points A and B, 2 trains departed simultaneously in the same direction. The speed of the first train was 80 km / h, and the speed of the second train was 110 km / h. The meeting took place 4 hours after the departure of the trains. How far apart are points A and B?

To solve the problem, first we find by how many km / h the speed of the second train is greater than the speed of the first train.

We get:

110 – 80 = 30 km / h.

We find the distance that the second train traveled before the meeting of the trains.

We multiply the speed of the lead by the time of the meeting.

We get:

30 * 4 = 120 km.

Answer:

Between cities A and B 120 km.