From points A and B, the distance between which is 19 km, two pedestrians left at the same time towards each

From points A and B, the distance between which is 19 km, two pedestrians left at the same time towards each other and met 9 km from A. Find the speed of a pedestrian going from A, if it is known that he was walking at a speed 1 km / h higher than a pedestrian coming from B, and made a half-hour stop on the way.

Let the speed of the pedestrian walking from point A be X km / h, then the speed of the pedestrian walking from point B will be (X – 1) km / h, since it is known that the first pedestrian walked at a speed 1 km / h higher than a pedestrian walking from B. The first pedestrian was on the way (9: X + 0.5) hours, since pedestrians met 9 km from A and he made a half-hour stop on the way. The second pedestrian was on the way (19 – 9): (X – 1) hours, since the distance between points A and B was 19 km. Knowing that two pedestrians left towards each other at the same time, that is, they spent the same time before the meeting, we make the equation: 9: X + 0.5 = (19 – 9): (X – 1); X ^ 2 – 3X – 18 = 0; X1 = – 3 – does not satisfy the condition of the problem, X2 = 6 (km / h) – the speed of a pedestrian walking from A.
Answer: 6 km / h – the speed of a pedestrian going from A



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