From points A and B, the distance between which is 280 km, at 9 am two cars left to meet each other.

From points A and B, the distance between which is 280 km, at 9 am two cars left to meet each other. At 11 o’clock they met at point C. It is known that AC refers to CB as 3: 4 Find: Distances AC and BC, Vehicle speeds, Time of arrival of vehicles at points A and B.

1. Let’s find first after what time they met:

11 – 9 = 2 (h).

2. Let’s calculate the distances AC and CB. Since there are only 7 parts (3 and 4), we find out how many km are in one part:

280/7 = 40 (km).

This means the distance of the AC:

40 x 3 = 120 (km).

And the distance NE:

40 x 4 = 160 (km).

3. Speed of the first car:

120/2 = 60 (km / h).

Second:

160/2 = 80 (km / h).

4. The first car will be at point B through:

280/60 = 4 2/3 (h)

The second car will be at point A through:

280/80 = 3.5 (h).

Answer: in the note.