From points A and B, the distance between which is 8 km, a bus simultaneously departed in one direction
From points A and B, the distance between which is 8 km, a bus simultaneously departed in one direction and a pedestrian exited at a speed of 4 km / h. Find the speed of the bus knowing that it caught up with the pedestrian in 15 minutes.
1) First, let’s translate 15 minutes into hours:
15 minutes = 0.25 hours.
2) From the condition of the problem, we know the distance between point A and B. We also know the time it took for the bus to catch up with the pedestrian. Let the speed of the bus be V1, and the speed of the pedestrian V2, then the speed of convergence will be V1 – V2. Let’s find it:
(V1 – V2) = S / t = 8 / 0.25 = 32 km / h – the speed of convergence between the bus and the pedestrian.
3) Since the speed of the pedestrian (4 km / h) and the speed of approach (32 km / h) are known to us, we find the speed of the bus (V1):
V1 – 4 = 32;
V1 = 32 + 4;
V1 = 36;
Answer: The bus speed is 36 km / h.