From points A and B, the distance between which is 94 km, a pedestrian and a cyclist set off to meet each other.

From points A and B, the distance between which is 94 km, a pedestrian and a cyclist set off to meet each other. A pedestrian’s speed is 16 km / h less than that of a cyclist. Find the speed of each if they met after 4 hours and the pedestrian made a half-hour stop on the way.

Decision:
1. Let x km / h be the speed of the pedestrian.
2. Then (x + 16) km / h is the speed of the cyclist.
3. Before meeting a pedestrian, the cyclist traveled a distance of 4 (x + 16) km. Before meeting the cyclist, the pedestrian covered the distance (4–0.5) x = 3.5x (km).
4. Let’s make an equation, solve it and find the speed of the pedestrian.
4 (x + 16) + 3.5x = 94.
4x + 64 + 3.5x = 94.
7.5x = 30.
x = 4 (km / h).
5. Find the speed of the cyclist.
x + 16 = 4 + 16 = 20 (km / h).
Answer: pedestrian speed – 4 (km / h), cyclist speed – 20 (km / h).



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