From the city A and B, the distance between which is 1200 km, 2 trains left at the same time towards each other.

From the city A and B, the distance between which is 1200 km, 2 trains left at the same time towards each other. The train from city A was traveling at a speed of 90 km / h. How fast did the train go from city B if the trains met after 6 hours?

Decision:

1. Let’s find the distance that the first train traveled before the meeting. To do this, we will use the formula:

s = v * t, where

s – distance; v is the speed; t is time.

s = 90 * 6 = 540 (km)

2. Now we can find the distance that the second train traveled before the meeting:

1200 – 540 = 660 (km)

3. Knowing the travel time and the distance traveled by the second train, we can find the speed of the second train by the formula:

v = s: t,

where v is the speed of movement; s – distance; t is time.

660: 6 = 110 (km / h)

Answer: the train from city B went at a speed of 110 km / h.



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