Initial data: coordinate equation x = x0 + 3t – t ^ 2.
To find the acceleration of a body, it is necessary to calculate the second-order derivative from the coordinate equation.
The first derivative: x ‘= V = (x0 + 3t – t ^ 2)’ = 0 + 3 * 1 – 2 * t = 3 – 2t.
The second derivative: x ” = V ‘= a = (3 – 2t)’ = 0 – 2 * 1 = -2 m / s ^ 2 (the movement of the body is slowed down).
Answer: The acceleration of the body is -2 m / s ^ 2; the acceleration modulus is 2 m / s ^ 2.
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