From the crossing of hybrid yellow non-pale mice with pale agouti mice, a splitting was obtained

From the crossing of hybrid yellow non-pale mice with pale agouti mice, a splitting was obtained: 52 pale agouti, 188 pale yellow, 41 pale yellow, 174 pale agouti (total 455). How is coloration inherited? Explain the results obtained. Determine the genotypes of the parents.

The resulting splitting 3: 3: 1: 1 Characterizes the crossing of the Mendelian type with the phenomenon of complete domination and independent inheritance of genes from a mice-diheterozygote with an individual heterozygous for one pair of genes and homozygous for the recessive genes of the second pair.

Let the yellow gene be G, then the agouti gene will be g.

Let the gene for pallor be N, then the gene for pallor will be n.

The first mouse is GgNn, it produces four types of germ cells – gn, GN, Gn, gN.

The second mouse – Ggnn (pale yellow), produces germ cells – Gn, gn.

The offspring are represented by options:

yellow pale mice (2Ggnn, GG nn);

yellow pale mice (GGNn, 2GgNn);

pale agouti mice (ggnn);

Agouti mice are not pale (ggNn).

The theoretically obtained splitting corresponds to the actual one from the condition of the problem.

Answer: yellow pale yellow mouse-diheterozygote (GgNn) and yellow pale mouse – heterozygous for the first trait (Ggnn).