From the loggia, located at a height of 21 meters, a ball was thrown horizontally at a speed of 17 m / s.

From the loggia, located at a height of 21 meters, a ball was thrown horizontally at a speed of 17 m / s. Determine the flight time of the ball and the distance from the base of the house to the point of its fall.

Task data: h (height at which the loggia is located) = 21 m; Vg (horizontal speed of the thrown ball) = 17 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The duration of the flight of the ball: h = Vw * t + a * t2 / 2 = 0 + g * t2 / 2, whence we express: t = √ (2h / g) = √ (2 * 21/10) = 2.05 with.

2) Distance from the base of the house to the point of falling of the thrown ball: S = Vg * t = 17 * 2.05 = 34.85 m.

Answer: The thrown ball was in flight for 2.05 s and fell 34.85 m from the base of the house.