From the point k of the plane, two inclined ones are drawn, one of which is 6 cm

From the point k of the plane, two inclined ones are drawn, one of which is 6 cm longer than the other. Oblique projections are 17 and 7 cm. Find oblique.

Let AC = 7 be the projection of the first oblique, and AO = 17 – the second. CO = 17 – 7 = 10. MВ = AB – AM = 6. Let AM = x – the first oblique, then AB = x + 6 – the second.

The AСM and AOB triangles are similar.

Means: AB / AO = AM / AC. That is: (x + 6) / 17 = x / 7;

x / 17 + 6/17 = x / 7;

x / 17 – x / 7 = – 6/17;

7x – 17 x = – 42;

– 10x = -42;

x = 4.2;

answer:

AM = x = 4.2;

AB = 4.2 + 6 = 10.2.