From the starting point, the car accelerated with constant acceleration to a speed of 20 m / s.

| March 15, 2021 | education

From the starting point, the car accelerated with constant acceleration to a speed of 20 m / s. Compare the acceleration lengths from 0 to 10 m / s and 10 to 20 m / s.

V0 = 0 m / s.

V1 = 10 m / s.

V2 = 20 m / s.

S12 / S01 -?

With uniformly accelerated movement, the path S traversed by the car is expressed by the formula: S = (V2 – V02) / 2 * a, where V is the final speed of movement, V0 is the initial speed of movement, a is the acceleration during movement.

S01 = (V1 ^ 2 – V0 ^ 2) / 2 * a.

S12 = (V2 ^ 2 – V1 ^ 2) / 2 * a.

S12 / S01 = (V2 ^ 2 – V1 ^ 2) * 2 * a / (V1 ^ 2 – V0 ^ 2) * 2 * a = (V2 ^ 2 – V1 ^ 2) / (V1 ^ 2 – V0 ^ 2 ).

S12 / S01 = ((20 m / s) ^ 2 – (10 m / s) ^ 2) / ((10 m / s) ^ 2 – (0 m / s) ^ 2) = 3.

Answer: the car on the second section will cover 3 times more distance than on the first one: S12 / S01 = 3.



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