From the vertex B of the expanded angle ABC, a ray BK was drawn so that the angle ABK = 108 °.

From the vertex B of the expanded angle ABC, a ray BK was drawn so that the angle ABK = 108 °. Beam BD is the bisector of the СBK angle. Calculate the degree measure of the angle DBK.

solution
angle СВK = 180 ° – 108 ° = 72 °
angle КВD = 72: 2 = 36 °



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