From the well, 0.5 m3 of water was slowly pumped out using a pump, the minimum work

From the well, 0.5 m3 of water was slowly pumped out using a pump, the minimum work done in this case is 30,000 What is the depth of the well?

Initial data: V (volume of water that was pumped out by the pump) = 0.5 m3; A (perfect minimum work) = 30,000 J.

Constants: ρ (water density) = 1000 kg / m3; g (acceleration due to gravity) = 10 m / s2.

The work that the pump performed when pumping out water can be represented in the form of the formula: A = F * S = ΔEp = m * g * h = ρ * V * g * h, whence h = A / (ρ * V * g).

Let’s calculate: h = 30,000 / (1000 * 0.5 * 10) = 6 m.

Answer: The depth of the well is 6 meters.