From two cities, the distance between which is 370 km, two cars simultaneously left towards each other

From two cities, the distance between which is 370 km, two cars simultaneously left towards each other. The speed of one of them is 4 km / h less than the speed of the second. Find the speed of each car, if 4 hours after they left, they had 18 km to go before the meeting.

Let the speed of the first car be x kilometers per hour, and the speed of the second car (x + 4) kilometers per hour. Then the first car covered 4 * x kilometers in 4 hours, and the second car covered 4 * (x + 4) kilometers during this time. We know that they had 18 kilometers to go before the meeting, and the distance between the cities was 370 kilometers. Let’s make the equation:

4 * x + 4 * (x + 4) + 18 = 370;

4 * x + 4 * x + 4 * 4 + 18 = 370;

8 * x + 16 + 18 = 370;

8 * x = 336;

x = 336: 8;

x = 42 kilometers per hour – the speed of the first car;

42 + 4 = 46 kilometers per hour – the speed of the second car.

Answer: 42 kilometers per hour; 46 kilometers per hour.