From two points, the distance between which is 1.2 km at the same time, 2 pedestrians began to move in one direction

From two points, the distance between which is 1.2 km at the same time, 2 pedestrians began to move in one direction V1 = 3.4 km / h. Determine the speed of the second if he caught up with the first after 45 minutes.

To solve this problem, let’s compose the coordinate equations for both pedestrians:
X2 = V2t
X1 = 1.2 + 3.4t, since the second caught up with the first (X1 = X2) after 45 minutes = 3/4 hours, we get the equation:
V2 * 3/4 = 1.2 + 3.4 * 3/4, hence
V2 = 5km / h