From two stations A and B, the distance between which is 18 km, two trains left simultaneously in the same direction.

From two stations A and B, the distance between which is 18 km, two trains left simultaneously in the same direction. The first train travels 0.8 km in one minute, and the second 0.6 km. In how many hours will the first train (leaving A) catch up with the second?

1. We translate km / min into km / h:

0.8 km / min x 60 = 48 km / h, 0.6 km / min x 60 = 36 km / h.

2. We take as x the time after which the train traveling at a higher speed from station A will catch up with another train following from station B:

3. We make the equation:

48x = 18 + 36x;

12x = 18;

x = 18: 12 = 3/2 = 1.5 hours.

Answer: the train coming from station A at a higher speed will catch up with the train coming from station B in 1.5 hours after departure.