From what height did the ball fall if upon impact it had a speed of 15 m / s?

Task data: V (speed of the taken ball on impact) = 15 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the initial height of the taken ball, apply the formula: S = h0 = (V ^ 2 – V0 ^ 2) / 2a = V ^ 2 / 2g.

Calculation: h0 = 15 ^ 2 / (2 * 10) = 11.25 m.

Answer: The original height of the taken ball was 11.25 m.



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