# The semi-major axis of Neptune’s orbit is 30.07 AU. Calculate the period of its revolution around the Sun.

October 9, 2021 | education

| To find the value of the period of Neptune’s rotation around the Sun, we apply Kepler’s third law: Tn ^ 2 / Tz ^ 2 = an ^ 3 / az ^ 3, whence we express: Tn = √ (an ^ 3 * Tz ^ 3 / az ^ 3).

Constants: en – semi-major axis of the planet Neptune’s orbit (by condition an = 30.07 AU); Tz is the period of the Earth’s rotation (T = 1 year); az is the semi-major axis of the Earth’s orbit (az = 1 AU).

Calculation: Tn = √ (an ^ 3 * Tz ^ 3 / az ^ 3) = √ (30.07 ^ 3 * 1 ^ 3/1 ^ 3) = 164.89 years.

Answer: The orbital period of the planet Neptune, according to the calculation, is 164.89 years.