From what height should the body fall so that its speed at the moment of falling is equal to 11 meters per second?

Given:

v = 11 meters per second – the speed of the body at the moment of its fall from a certain height;

g = 9.8 meters per second squared – the acceleration of gravity.

It is required to determine h (meter) – from what height the body should fall.

Since the problem statement is not specified, the energy losses associated with work against the force of air resistance will not be taken into account. Then, according to the law of conservation of energy:

Ekinetic (at the moment of falling) = Epotential (at height h);

m * v ^ 2/2 = m * g * h, where m is body weight;

v ^ 2/2 = g * h;

h = v ^ 2 / (2 * g) = 11 ^ 2 / (2 * 9.8) = 121 / 19.6 = 6.2 meters (the result has been rounded to one decimal place).

Answer: the body must fall from a height of 6.2 meters.