From what height was the object dropped if it fell to the surface of the ground after 3 seconds?

To find the height from which the object in question was dropped, we apply the formula: S = V0 * t + a * t ^ 2/2 = 0 + g * t ^ 2/2.

Variables and constants: g – gravitational acceleration (g ≈ 10 m / s2); t – the duration of the fall of the object under consideration (t = 3 s).

Calculation: S = g * t ^ 2/2 = 10 * 3 ^ 2/2 = 45 m.

Answer: The object in question was dropped from a height of 45 m.