Full hydrogenation of 140 g of propyne under normal conditions requires a volume of hydrogen.
| January 2, 2021 | education
The reaction equation for the complete hydrogenation of propyne:
C3H4 + 2H2 (cat.) = C3H8
Amount of propyne substance:
v (C3H4) = m (C3H4) / M (C3H4) = 140/40 = 3.5 (mol).
According to the reaction equation, 1 mol of C3H4 reacts with 2 mol of H2, therefore:
v (H2) = v (C3H4) * 2 = 3.5 * 2 = 7 (mol).
Thus, for the complete hydrogenation of propyne under normal conditions (n.a.), hydrogen will be required in volume:
V (H2) = v (H2) * Vm = 7 * 22.4 = 156.8 (l).
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