Gas at 27 ° C. To what temperature was the gas heated if its volume doubled at a constant pressure?

According to the Gay – Lussac law: p = const, then V / T = const.
Thus, we write the following equation:
V1 / T1 = V2 / T2, while V2 = 2V1.
Let’s substitute the values we know:
V1 / 27 ° C = 2V1 / T2.
Therefore, T2 * V1 = 2V1 * 27 ° C.
Reduce both sides of the equation by V1:
T2 = 2 * 27 ° C.
T2 = 54 ° C.

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