Gas at a pressure of 6 atm and a temperature of 293K occupies a volume of 586 liters.
| April 4, 2021 | education
Gas at a pressure of 6 atm and a temperature of 293K occupies a volume of 586 liters. Find the volume occupied by the same mass of gas at a temperature of 248K and a pressure of 4 * 10 ^ 5Pa.
Initial data: P1 (gas pressure) = 6 atm = 6 * 101 325 Pa; T1 (gas temperature) = 293 K; V1 (volume occupied by gas) = 586 l = 0.586 m ^ 3.
Final data: P2 (gas pressure) = 4 * 10 ^ 5 Pa; T2 (gas temperature) = 248 K.
The volume of this gas under the given conditions is calculated from the ratio:
P2 * V2 / T2 = P1 * V1 / T1.
V2 = P1 * V1 * T2 / (T1 * P2).
Calculation:
V2 = 6 * 101 325 * 0.586 * 248 / (293 * 4 * 10 ^ 5) = 0.754 m ^ 3 (754 l).
Answer: Under the given conditions, the gas occupies a volume of 0.754 m ^ 3 (754 liters).
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