Gas at a temperature of 300K occupies a volume of 250 cm ^ 3. What volume will the same

Gas at a temperature of 300K occupies a volume of 250 cm ^ 3. What volume will the same gas take if its temperature rises by 30 K?

If the pressure is constant, and only the volume and temperature change, then the Gay-Lusac law applies:

V1 / T1 = V2 / T2, where V1 and T1 are the initial volume and temperature, V2 and T2 are the final values of the volume and temperature.

V2 = V1T2 / T1 = (25 cm ^ 3/330 K) / 300 K = (25 * 11) / 10 cm ^ 3 = 26.5 cm ^ 3.

Answer: 26.5 cm ^ 3.



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