Gas received 300 J, its internal energy increased by 200 J, what is the work done by the gas?
| January 12, 2021 | education
Q = 300 J.
ΔU = 200 J.
A -?
According to the first law of thermodynamics: the amount of heat Q, which is imparted to the gas, goes to increase its internal energy ΔU and to work on the external forces A.
Q = ΔU + A.
Let’s express the work from the formula:
A = Q – ΔU.
A = 300 J – 200 J = 100 J.
Answer: the gas did the job A = 100 J.
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