Gas volume 20L. If the gas is isobarically cooled by 100 K, its volume will be equal to 10 liters
| January 13, 2021 | education
Gas volume 20L. If the gas is isobarically cooled by 100 K, its volume will be equal to 10 liters, then the initial gas temperature is equal to.
Given: V1 (initial gas volume) = 20 l; T1 – T2 = ΔT (change in gas temperature) = 100 K; V2 (gas volume after cooling) = 10 l; the gas cooling process is isobaric.
The initial gas temperature is determined from the equality: V1 / T1 = V2 / T2 = V2 / (T1 + 100).
V1 * (T1 + 100) = V2 * T1.
20 * (T1 + 100) = 10 * T1.
20T1 + 2000 = 10T1.
10T1 = 2000 and T1 = 2000/10 = 200 K.
Answer: The initial gas temperature was 200 K.
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